Question

A cell of emf (E) and internal resistance r is connected across a variable
external resistance R. The graph of terminal potential difference V as a
function of R is -
V
VA
VA
E
--------
→R
0
->
0
(a)
(b)
(C)
(d)

Answer 1

Answer:

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Explanation:

Answer 2

The graph of the potential difference V and function R.

Explanation:

Given that,

emf of cell = E

External resistance = R

Potential difference = V

Internal resistance = r

According to diagram,

Current in the circuit is

$I=\dfrac{E}{R+r}$

Potential difference across R.

$V=IR$

Put the value of I

$V=\dfrac{E}{R+r}\times R$

$V=\dfrac{E}{1+\dfrac{r}{R}}$

When, R = 0, V = o

R = ∞, V = E

Hence, The graph of the potential difference V and function R.

Learn more :

Topic : potential difference

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