a cell of internal resistance 0.5ohms and emf 2volts is connected to resistance of 9.5ohms what is the p. d across terminals of cell
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Explanation:
Current, I=
R
total
V
=
0.5+9.5
2
=0.2A=0.2Cs
−1
Number of electron =
1.6×10
−19
Q
total
=
1.6×10
−19
It
=
1.6×10
−19
0.2×1
Number of electron=1.25×10
18
nos.
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