A cell of internal resistance 2 ohms supplies current to a 6-ohm resistor.the efficiency of the cell
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Answer:
75%
Explanation:
Think of the 6 ohm resistor as three 2 ohm resistors. Three 2 ohm resistors is in the load, and one 2 ohm resistor is in the source. That makes a total of four 2 ohm resistors, one of which is wasting power. 1/4 of the power is wasted in the battery, and 3/4 of the power is going to the load. The efficiency is 75%.
or
Efficiency = IR/I(R+r) x 100
= 6/(2+6) x 100
= 75%
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