Question

A cell of negligible internal resistance and emf 1.2 V is
connected in series with three resistors of resistances 1ohm,2ohm
and 3ohm respectively. What is the potential difference across
2ohm resistor?
(a) 0.2 V
(b) 0.4 V
(d) 0.6 V
(d) 0.8V​

Answer 1

Answer:

0.4v as v=1.2v in whole circuit and resistance in series=1+2+3=6 ohm current=1.2/6=0.2A

so r=2ohm

I=0.2A

then V=IR

=0.2.2=0.4v

Answer 2

Hello Friend..!!

The answer of u r question is..!!

Option.A

Thank you..!!