a cell of negligible resistance and EMF 2 volt is connected to series combination of 2, 3 and 5 ohm the potential difference in volts between the terminal of 3 ohm resistance will be?
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Answer:0.6 V
Explanation: equivalent resistance of series commection is
2+3+5=10 ohm
Therefore,,current,,I=V/R
I=2/10=0.2A
Now potential difference in 3 ohm resistance is
V=I×R. (Current is same in series)
V= 0.2×3= 0.6 V
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