A cell phone company found that 75% of all customers want text messaging on their Phones, 80% want photo capability, and 65% want both. What is the probability that a customer will want at least one of theses.
Answers
Let's say that 75% of smartphone customers want text messaging; 80% want photo capability; 65% want both. What is the probability that a customer wants photo capability, given that he wants text messaging? 65/75=13/15 or about 86.7%.
Hope this helps u
Given,
In a cell phone company;
Percentage of all customers who want text messaging on their phones = 75%
Percentage of all customers who want photo capability on their phones = 80%
Percentage of all customers who want both = 65%
To find,
The probability that a customer chosen at random will want at least one of these.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically,
The probability of occurrence of a favorable event = P (favorable event)
= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)
= (Total number of occurrence of the favorable event) / (Total number of trials)
As per the given question;
The percentage of all customers who want only text messaging on their phones
= Percentage of all customers who want text messaging on their phones - percentage of all customers who want both
= 75% - 65% = 10%
And, the percentage of all customers who want only photo capability on their phones
= Percentage of all customers who want photo capability on their phones - percentage of all customers who want both
= 80% - 65% = 15%
Now,
The percentage of all customers who want at least one of these
= Percentage of all customers who want only text messaging on their phones + percentage of all customers who want only photo capability on their phones + percentage of all customers who want both
= 10% + 15% + 65% = 90%
Now,
The probability that a customer chosen at random will want at least one of these
= (Total number of occurrence of the favorable event) / (Total number of trials)
= (percentage of all customers who want at least one of these)/(total percentage of all the users)
= 90%/100% = 0.9
Hence, the probability that a customer chosen at random will want at least one of these is equal to 0.9.