Question

A cell phone is at rest on a tabletop and the phone’s owner flicks the phone with their fingers, which applies a 0.01 N force to the phone. The phone is accelerated at a rate of 0.1 m/s2 in the direction of the flick. What is the mass of the phone?

Answer 1

Explanation:

Force=0.01N=F

Acceleration=a=0.1m/s^2

Mass=m

\begin{gathered}\\ \sf\longmapsto F=ma\end{gathered}

⟼F=ma

\begin{gathered}\\ \sf\longmapsto m=\dfrac{F}{a}\end{gathered}

⟼m=

a

F

\begin{gathered}\\ \sf\longmapsto m=\dfrac{0.01}{0.1}\end{gathered}

⟼m=

0.1

0.01

\begin{gathered}\\ \sf\longmapsto m=0.1kg\end{gathered}

⟼m=0.1kg

m=100g

Answer 2

Force=0.01N=F

Acceleration=a=0.1m/s^2

Mass=m

m=100g