A cell was prepared by dipping a copper wire and a saturated calomel electrode, itself +0.242 V (she), into CuSO4 solution with the copper ion activity at 0.1 M. Using the Nernst equation chosen in question 3, calculate the cell voltage, given that EoCu2+,Cu = 0.339 V (she). Options:
0.038 V
0.067 V
0.309 V
0.280 V
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Answer:
According to Nernst equations, E=E
o
−(0.0591/n)logQ
E
RP
1
=E
o
+
2
0.059
log[Cu
2+
]
1
.........(1);
[Cu
2+
]
2
=C
1
×
10
1
So now, E
RP
2
=E
o
+
2
0.059
logC
1
×
10
1
.........(2)
So, E
2
−E
1
=−0.030V
So reduction electrode potential decreases by 0.030 V
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