A cell with zero internal resistance and emf of 2v is connected across 2,3 and 5ohm. The potential difference across 3ohm resistor will be
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Answer:
0.6v
Explanation:
equivalent resistance of series commection is
2+3+5=10 ohm
Therefore,,current,,I=V/R
I=2/10=0.2A
Now potential difference in 3 ohm resistance is
V=I×R. (Current is same in series)
V= 0.2×3= 0.6 V
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