Question

A cement block of weight 100n has sides of length 10cm,20cm,24cm calculate the pressure exerted by the when it is lying on the side with least area​

Answer 1

Answer:

(i) 5000Pa

(ii)2083Pa

Step-by-step explanation:

Force = 100N

Least area = 10cm*20cm=200cm^2=0.02m^2

Greatest area  =20cm*24cm = 480cm^2 = 0.048cm^2

Pressure=Force/Area

Least Area Pressure=100N/0.02m^2=5000N/m^2=5000Pa

Greatest area pressure=100N/0.048m^2=6250N/3m^2=2083Pa