Question

A centical water tank is 6m long, 6m broad and 6m deep. Find the cost of plaster the floor of wall of the tank at the rate of rs 10/m²

Answer 1

Answer:

The dimensions of the room are -

• Long = 6m
• Broad = 6m
• Deep = 6m.

To find the cost of plastering the floor of the water tank we need to find the area for plastering.

→ 2 (l+b) × h + lb

→ 2 (6+6) × 6 + 6×6

→ 2 × 12 × 6 + 36

→ 180 m².

_________________________

Therefore,

Total cost = 180 × 10

→ 1800 Rs per m².

Answer 2

Answer:

Given:

• A water tank is 6 m long, 6 m broad and 6 m deep.

Find:

• Find the cost of plaster the floor of wall of the tank at the rate of rs 10/m².

Using formula:

⇢ $\tiny{\sf{\underline{\boxed{\blue{\sf{2 (Length + Breadth) \times Height + (Length \times Breadth) }}}}}}$

Calculations:

⇢ $\sf{2 (6 + 6) \times 6 + (6 \times 6)}$

⇢ $\sf{(2 \times 12) \times 6 + 36}$

⇢ ${\sf{\underline{\boxed{\pink{\sf{180 \: m^{2} }}}}}}$

Using the above value, we find the total cost:

⇢ $\sf{180(10)}$

⇢ ${\sf{\underline{\boxed{\pink{\sf{1800 \: m^{2}}}}}}}$

Therefore, rupees 1800 is the cost of m².