Question

a cera certain block weighs 15 Newton in air . it weighs 12 Newton when immersed in water. when immersed in another liquid , it weighs 13 Newton. the relative density of a) the block b) The Other liquid are ​

Answer 1

The relative density of

(a) The block is 5

(b) The other liquid is 2/3

Explanation:

Let the volume of the Block be V

Weight of the Block in air W = 15 N

If the density of the block is $\rho_b$

Then

$V\rho_b g=15$  .............(a)

When the block is placed in water it will replace water equal to its volume

The weight of this water will be equal to the bouyant force upwards on the block

Therefore,

The weight of the block in water

= Weight of the block in air - Bouyant force

$\implies 12=15-V\rho_w g$  (where $\rho_w$ is the density of water)

$\implies V\rho_w g=3$  ..........(1)

Similarly if the density of the liquid is $\rho_l$

Then

$13=15-V\rho_l g$

$\implies V\rho_l g=2$  .........(2)

Dividing (2) by (1)

$\frac{\rho_l}{\rho_w}=\frac{2}{3}$

$\implies \rho_l=\frac{2}{3}\times \rho_w$

Thus the relative density of the liquid is 2/3

Again from equation (a) and (1)

$\frac{\rho_b}{\rho_w}=\frac{15}{3}$

$\implies \rho_b=5\rho_w$

Therefore, the relative density of the block is 5

Hope this answer is helpful.

Know More:

Q: A block weights 15 N in air and 12 N when immersed in water. Find the specific gravity of the block.

Click Here: https://brainly.in/question/3116989

Q: A wooden block of mass 400 gram float vertically in a liquid of density 0.8 gram/cm cube... if the volume of the block is 625 cm cube....find the volume of the block above the surface of the liquid.

Click Here: https://brainly.in/question/6058611