Question

A ceramic tile measuring 50cm X 50 cm has been designed to bear a pressure of 40N/m2. Will it withstand a force of 5N?

Answer 1

Answer:

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Explanation:

Given,

Side of tile = 50cm

First we change it to Metre

We know,

1m = 100cm

100 cm = 1 m

1 cm = 1/100 m

50 cm = 50/100 m

50 cm = 1/2 m

50 cm = 0.5 m

Area of tile = (side)^2

= 0.5 x 0.5

Area of tile = 0.25 m^2

It is given that tile can carry a pressure of 200N/m^2. If the force applied by this pressure is F,

F = Pressure x Area to tile

F = 200 x 0.25

F = 2 x 25

F = 50 N

Hence, It can withstand any force less than 50 N