A certain amount is distributed equally among certain boys. If there were 5 boys more each would
have received ` 8 less, while if there were 4 boys less, each would have received ` 10 more. Find the
amount distributed and the number of boys.
Answers
Answered by
3
Answer:
sorry I didn't know about it
Answered by
5
Answer:
800 & 40
Step-by-step explanation:
Number of boys- x
Amount every boy gets - y
Total amount= xy
With 5 boys more amount is: (x+5)(y-8)=xy
With 4 boys less amount is: (x-4)(y+10)=xy
Simplifying the above and also comparing:
1. (x+5)(y-8)=xy =>xy-8x+5y-40=xy => 5y-8x-40=0
2. (x-4)(y+10)=xy=> xy+10x-4y-40=xy => 10x-4y-40=0 => 5x-2y-20=0
3. (x+5)(y-8)=(x-4)(y+10) =>5y-8x-40=10x-4y-40 =>9y=18x =>y=2x
Considering this in first equation we get:
10x-8x=40
2x=40
x=20, y=40, xy=800
So number of boys is 40 and amount is 800
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