Question

a certain amount of a gas 3 L at 0.6 bar . find the change in it volume when the pressure is changed to 0.2 bar?

a) increases in 9 L
b) increases in 6L
c) decreases by 9 L
d) decreases by 9 L

Answer 1

Answer:

The volume increases by 6L

Explanation:

Boyle's Law state that Pressure is inversely proportional to Volume provided the temperature remains constant.

=> P₁V₁/T₁ = P₂V₂/T₂

Here, Temperature is constant that is, T₁ = T₂

=> P₁V₁ = P₂V₂      

Here, P₁ = Pressure (initial) = 0.6 bar

         V₁ = Volume (initial) = 3L

         P₂ = Pressure (final) = 0.2 bar

         V₂ = Volume (final) = Let it be V₂

Substituting the above values in the above equation

=> 0.6*3 = 0.2*V₂

=> V₂ = 9L

Change in volume = Final - Initial

                               = 9L - 3L

                               = 6L

Therefore, the volume increases by 6L