a certain amount of metal whose equivalent mass is 28 displaces 0.7 l of H2 at S. T. Pfrom an acid hence mass of element is
Answers
Answered by
15
1 mole of H2 at STP occupies volume = 22.4 L
No. of moles of 0.7 L H2 at STP = 0.7/22.4 = 0.0313 moles.
Weight of element (X) = Moles of H2 x eq. wt. of the metal x mass of H2
X = 0.0313 x 28 x 2
X = 1.7528 grams.
No. of moles of 0.7 L H2 at STP = 0.7/22.4 = 0.0313 moles.
Weight of element (X) = Moles of H2 x eq. wt. of the metal x mass of H2
X = 0.0313 x 28 x 2
X = 1.7528 grams.
sunil58:
bro I have done mistake at dividing h2 /22.4 thankd
Similar questions