a certain amount of metal whose equivalent mass is 28 displaces 0.7 L of H2 at STP from an acid , hence the mass of the element is? Explain in detail.
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1 mole of H2 at STP occupies volume = 22.4 L
No. of moles of 0.7 L H2 at STP = 0.7/22.4 = 0.0313 moles.
Weight of element (X) = Moles of H2 x eq. wt. of the metal x mass of H2
X = 0.0313 x 28 x 2
X = 1.7528 grams.
No. of moles of 0.7 L H2 at STP = 0.7/22.4 = 0.0313 moles.
Weight of element (X) = Moles of H2 x eq. wt. of the metal x mass of H2
X = 0.0313 x 28 x 2
X = 1.7528 grams.
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