A certain amount of money is distributed among A,B and C. A gets 3/16 and B gets 1/4 of the whole amount. if C gets ₹81,then B gets
Answers
Answered by
39
hi
A+B+C = x
3x/16 + x/4 + 81 = x
3x + 4x + 81*16 = 16x
9x = 1296
x = 144
so B gets
= x/4
= 144/4
= 36 Rs
Hope it helped !
Let me know if any doubts
Cheers !!!
A+B+C = x
3x/16 + x/4 + 81 = x
3x + 4x + 81*16 = 16x
9x = 1296
x = 144
so B gets
= x/4
= 144/4
= 36 Rs
Hope it helped !
Let me know if any doubts
Cheers !!!
shshank28691:
galat h
yes one second
now check
answer aa gaya
aap add karne me galti kiye h
add karne per 9X aata
aap 6X likh diye the
main 16 mulitply karna bhool gaya rhs mein
ab dekho ab sahi hai
Answered by
0
Answer:
pls mark me as brainliest
Step-by-step explanation:
Let the total amount = Rs x
A's share =
16
x,B
′
sshare=
x
1
x
∴C
′
sshare=x−(
16
3
x+
4
1
x)=x−
16
7
x=
16
9
x
Given
16
9x
=81⇒x=
9
81×16
=144
∴B
′
sshare=
4
1
×Rs144=Rs36
Similar questions