Question

A certain aqueous solution of FeCl3 [formula mass - 162] has a density of 1.1 g/mL and contains 20.0 % FeCl3.

Answer 1

Molar mass of FeCl3 = 56 +3 × 35.5

= 162.5 g

20 % by Mass/ mass means 200 g out of 1000 g

Volume of 1000 g solution = 1000/1.1= 0.909 L

Molarity = mass of solute/ molar mass x volume of solution in litres

= 200/162 5 ×0.909 =1.35 M