A certain automobile manufacturer claims that its super-deluxe sports car will accelerates from rest to a speed of 21.0ms^(-1) in 4.0s.Under the important assumption that the acceleration is constant.Find the distance the car travels in 4^( th ) second.
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(a) Assuming a constant acceleration
a=
t
v
f
−v
i
=
8.00s
42.0m/s
=5.25m/s
2
(b) Taking the origin at the original position of the car,
x
f
=
2
1
(v
i
+v
f
)t=
2
1
(42.0m/s)(8.00s)=168m
(c) From v
f
=v
i
+at, the velocity 10.0s after the car starts from rest is:
v
f
=0+(5.25m/s
2
)(10.0s)=52.5m/s
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