Science, asked by gbgunj789, 5 months ago

A certain balloon maintains an internal gas pressure
of Po = 100 kPa until the volume reaches Vo = 20 m3.
Beyond a volume of 20 m®, the internal pressure varies
as P = Po + 2(V - V.), where P is in kPa and Vis
in m?
Initially, the balloon contains helium gas at 20°C,
100 kPa with a 15 m3 volume. The balloon is then
heated until the volume becomes 25 m3 and the
pressure is 150 kPa. Assume ideal gas behaviour
for helium.
the work done by the entire process in kj and the final temperature of the balloon in kelvin is?​

Answers

Answered by abhinavmishra07
0

Answer:

chal bechomudghdsksnjssj

Answered by binayaksingh14
0

Answer:

733 K,1083 KJ

Explanation:

solved by integrating pv for different range of volume

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