A certain comet is visible on earth once in every x years - that is, it has a periodicity of exactly x years. Three of the years in which it was seen are 1780, 1861 and 1987. Which of these could be the value of x?
Answer Options
Option A 2
Option B 5
Option C 6
Option D 9
Please explain this in a proper step by step manner pls as fast as possible
Answers
Answered by
1
Step-by-step explanation:
1861-1780
=81
81 is divisible by 9
answer option d
Answered by
2
Answer- Option D 9
Step 1- Subtract 1780 from 1861 and 1861 from 1987.
Step2- 1861 - 1780 = 81 and 1987 - 1861 = 126
Step3- Now out of all the given options, 81 and 126 are both divisible by 9.
Therefore, an appropriate periodicity would be 9.
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