A certain compound contains 11.5 g of sodium 16.1 g of sulphur and 12 g of oxygen calculate the empirical formula and molecular formula of the compound
Answers
Answer:
Na
2
S
2
O
3
.5H
2
O
Explanation:
Element Relative number of atoms Simplest ratio of whole numbers
Sodium
23
18.6
=0.8
0.8
0.8
=1
Sulphur
32
25.8
=0.8
0.8
0.8
=1
Hydrogen
1
4.03
=4.03
0.8
4.03
=5
Oxygen
16
51.58
=3.22
0.8
3.22
=4
Empirical formula =NaSH
5
O
4
Molecular weight=248
Empirical formula weight=23+32+5+64=124
n=
124
248
=2
Molecular formula=NaSH
5
O
4
×2=Na
2
S
2
H
10
O
8
Since, all the hydrogen in the compound is in combination with the oxygen as water of crystallization so 10 atoms of hydrogen and 5 atoms of oxygen.
So, the formula becomes Na
2
S
2
O
3
.5H
2
O.