Question

A certain compound has molecukar formula x4o6.8f 10 gm of comlound

Answer 1

Molecular formula of the compound = X4O6

10 grams of X4O6 contains 5.72 grams of X.

Percentage of X in given molecule = (5.72*100)/10

Percentage of X = 57.2 %

Percentage of Oxygen = 100- Percentage of X

= 100- 57.2

= 42.8%

Gram molecular weight 6 atoms of Oxygen (O6) = 6*16 = 96 grams

42.8% of Oxygen has a mass of 96 grams.

Then 57.2 % of X will have a mass of = (57.2*96)/42.8

= 128.29 grams

4 atoms of X has a mass = 128.29 grams

1 atom of X will have a mass = (128.29)/4

= 32.075

Gram atomic mass of X = 32.075 grams

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