Question

A certain compound has molecular formula X4O6 . If 10 gm of compound contain 6.o6 gm of x the atomic mass of X

Answer 1

Mass of the Compound (X₄O₆) = 10 g.

Mass of the Element X in the Compound = 6.06 g.

Let the Atomic Mass of the Element X be a.

∴ Mass of X in the compound = 4a.

∴ Molecular Mass of the Compound = a × 4 + 16 × 6

   = 4a + 96

Now,

Mass of X/Mass of the compound = At. Mass of the X/Mol. Mass of the Compound.

⇒ 6.06/10 = 4a/(4a + 96)
⇒ 6.06/10 = 4a/4(a + 24)
⇒ 0.606 = a/(a + 24)
⇒ 0.606(a + 24) = a
⇒ 0.606a + 14.544 = a
⇒ a - 0.606a = 14.544
⇒ 0.394a = 14.544
⇒ a = 14.544/0.394
∴ a = 36.9
∴ a = 37 a.m.u.

Hence, the Atomic Mass of the Element X is 37 a.m.u.

Hope it helps.