Question

A certain compound has the molecular formula X4O6.If 10.0g of compound contains 6.06g of X,the atomic mass of X is

Answer 1

Hello Dear.

Mass of the Compound (X₄O₆) = 10 g.
Mass of the Element X in the Compound = 6.06 g.

Let the Atomic Mass of the Element X be a.
∴ Mass of X in the compound = 4a.

∴ Molecular Mass of the Compound = a × 4 + 16 × 6
   = 4a + 96
  

Now,
Mass of X/Mass of the compound = At. Mass of the X/Mol. Mass of the Compound.
⇒ 6.06/10 = 4a/(4a + 96)
⇒ 6.06/10 = 4a/4(a + 24)
⇒ 0.606 = a/(a + 24)
⇒ 0.606(a + 24) = a
⇒ 0.606a + 14.544 = a
⇒ a - 0.606a = 14.544
⇒ 0.394a = 14.544
⇒ a = 14.544/0.394
∴ a = 36.9
∴ a ≈ 37 a.m.u.


Hence, the Atomic Mass of the Element X is 37 a.m.u.


Hope it helps.

Answer 2

Answer:

37 Amu

Explanation:

Mass of the Compound (X₄O₆) = 10 g.

Mass of the Element X in the Compound = 6.06 g.

Let the Atomic Mass of the Element X be a.

∴ Mass of X in the compound = 4a.

∴ Molecular Mass of the Compound = a × 4 + 16 × 6

= 4a + 96

Now,

Mass of X/Mass of the compound = At. Mass of the X/Mol. Mass of the Compound.

⇒ 6.06/10 = 4a/(4a + 96)

⇒ 6.06/10 = 4a/4(a + 24)

⇒ 0.606 = a/(a + 24)

⇒ 0.606(a + 24) = a

⇒ 0.606a + 14.544 = a

⇒ a - 0.606a = 14.544

⇒ 0.394a = 14.544

⇒ a = 14.544/0.394

∴ a = 36.9

∴ a ≈ 37 a.m.u.