Math, asked by sknidhi, 4 days ago

a certain concrete mix needs cement, fine aggregate, and coarse aggregate in the ratio 1:2:4. if the contractor has 25 kg of fine aggregate, how much quantity of the cement and that of the coarse aggregate is required to prepare the mix?​

Answers

Answered by taanyagupta242
2

Step-by-step explanation:

2x=25

x=25/2

cement=1x=1×25/2=12.5kg

coarse aggregate= 4x=4×25/2=50kg

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