A certain force acting on a 20 kg mass changes it's velocity from 2m/s to 5m/s in 6 sec. Calculate the work done by the force and power exerted by the force.
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Mass = 20 kg
u = 2m/s
v = 5m/s
t = 6s
a = 5 - 2 / 6
= 3/6 = 1/2 m/s² = 0.5 m/s²
s = ut + 1/2 at²
= 2 X 6 + 1/2 X 1/2 X 36
= 12 + 1/4 X 36
= 12 + 9
= 21 m
F = m a
= 20 × 0.5
= 10 N
W = F s
= 10 X 21
= 210 N m
P = W / t
= 210 / 6 = 70 /2 = 35 Nms⁻¹ Or watt
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______________________________________________________________
Mass = 20 kg
u = 2m/s
v = 5m/s
t = 6s
a = 5 - 2 / 6
= 3/6 = 1/2 m/s² = 0.5 m/s²
s = ut + 1/2 at²
= 2 X 6 + 1/2 X 1/2 X 36
= 12 + 1/4 X 36
= 12 + 9
= 21 m
F = m a
= 20 × 0.5
= 10 N
W = F s
= 10 X 21
= 210 N m
P = W / t
= 210 / 6 = 70 /2 = 35 Nms⁻¹ Or watt
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