Physics, asked by yadunandan, 1 year ago

A certain force acting on a 20 kg mass changes it's velocity from 2m/s to 5m/s in 6 sec. Calculate the work done by the force and power exerted by the force.

Answers

Answered by Anonymous
5
Hey!
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Mass = 20 kg 
u = 2m/s 
v = 5m/s 
t =  6s 
a =  5 - 2 / 6 
   = 3/6 = 1/2 m/s² = 0.5 m/s²
s = ut + 1/2 at²
   = 2 X 6 + 1/2 X 1/2 X 36 
   = 12 + 1/4 X 36 
   = 12 + 9 
   = 21 m
F = m a 
   = 20 × 0.5 
   = 10 N 
W = F s 
    = 10 X 21 
    = 210 N m 
P = W / t
   =  210 / 6 = 70 /2 = 35 Nms⁻¹ Or watt 
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