Question

a certain force acting on a body of mass 2 kg increases its velocity from 6 metre per second to 15 M per second in 2 second work done by the force during the interval will be​

Answer 1

Answer:

189J

Explanation:

HERE

m=2kg

u=6m/s

v=15m/s

t=2s

a=v-u/t=

=15-6/2

=4.5m/s²

S= ut +1/2at²

=12+9

=21m

also f=ma

2*4.5=9N

so work done = force*displacement

=9*21

189J

Answer 2

Answer:work = change in kinetic energy

So,

》(1/2×m×v_final kinetic energy)-(1/2×m×b_initial kinetic energy)

》1/2×2×(15^2)-1/2×2×(6^2)

》225-36

》189

Explanation: