Question

a certain force acting on a body of mass 40 kg and changes its velocity from 5 metre per second to 2 metre per second calculate the work done by the force​

Answer 1

$\huge\mathfrak\red{Answer ;}$

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$<b>Given,$

Mass = 40kg

Initial Velocity = 5ms^-1

Final Velocity = 2ms^-1

Initial Kinetic Energy = 1/2 × m × (v)^2

= 1/2 × 40 × 25

= 500 Joules

Final Kinetic Energy = 1/2 × m × (v)^2

= 1/2 × 40 × 4

= 80 Joules

Therefore, Work done = Change in Kinetic Energy

= Final k(e) - initial k(e)

= 80 - 500

= -420 J.

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