Question

A certain force acting on a mass of 15kg for 3s, Give it a velocity of 2m/s. find the impulse on the ball and average force applied by the player if he is able to stop the ball in 0.18s ?​

Answer 1

Explanation:

Impulse=m(v-u)

            =15(0-2)

            = -30Ns

a=v-u/t

 =0-2/0.18

 = -11.11m/s^2

F=ma

 = 15*11.11

 =166.65

Answer 2

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Impulse=m(v-u)

            =15(0-2)

            = -30Ns

a=v-u/t

 =0-2/0.18

 = -11.11m/s^2

F=ma

 = 15*11.11

 =166.65