Question

a certain force acts on a body at rest if after 10 seconds the body moves with a velocity of 20m/s and if its mass is 3kg find th magnitude of the force acting on the body​

Answer 1

Answer:

Provided that:

• Initial velocity = 0 m/s
• Time = 10 seconds
• Final velocity = 20 m/s
• Mass = 3 kilograms

Don't be confused! Initial velocity cames as zero because the body is at rest initially!

To calculate:

• The force

Solution:

• The force = 6 Newton

Using concept:

• Force formula

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{F \: = m \cdot \bigg \lgroup \dfrac{v-u}{t} \bigg \rgroup}}}}}}$

Where, a denotes acceleration, u denotes initial velocity, F denotes force v denotes final velocity, m denotes mass and t denotes time taken.

Required solution:

$:\implies \sf F \: = m \cdot \bigg \lgroup \dfrac{v-u}{t} \bigg \rgroup \\ \\ :\implies \sf F \: = 3 \cdot \bigg \lgroup \dfrac{20-0}{10} \bigg \rgroup \\ \\ :\implies \sf F \: = 3 \cdot \bigg \lgroup \dfrac{20}{10} \bigg \rgroup \\ \\ :\implies \sf F \: = 3 \cdot 2 \\ \\ :\implies \sf F \: = 6 \: Newton \\ \\ :\implies \sf Force \: = 6 \: Newton$