A certain force acts on a body of mass 10 kg and changes its velocity from 2m/sec to 5m/sec calculate the work done by the force
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Answered by
0
Answer:
work done by all Forces = ∆KE
W = ∆KE
W = 1/2m (Vf^2 - vi^2)
w = 1/2 × 10 (25-4)
W = 105Joule
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Answered by
1
Answer:
F = Ma
to calculate a we need time in which the velocity changed from 3 to 5
if you mean 1 second then..!
a will be 3m/s²
F = 10 × 3 = 30N
w = f × d
to calculate displacement
s = ut + 1/2at²
s= 3×1 + 1/2×3×1²
s= 4.5m
w = 30 × 4.5
w = 135 J
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