Question

A certain force acts on a body of masses 10kg and changes its velocity to 2m\s to 5m\s. Calculate work done by force

Answer 1

P=m*v and p=10*(5-3)= 30kgm/s

Answer 2

given
m= 10kg
V= 5 m/s
U = 2 m/s
we know that
V^2 = U^2+ 2as
then
a = (V^2- U^2)/2s
world one = FS = ma × s
= m { (V^2-U^2)/2s)}× s
= 10×{[25-4]/2
= 105 J _____Ans
or u can calculate directly by
W = 1/2(m.V^2)
where V = final velocity - Initial velocity