Question

A certain force exerted for 0.5s raise the speed of an object from 2.4m/s to 4.9 m/s. Later, the same force is applied for 2.5s .How much does the speed of object change in 2.5 s

Answer 1

v=u+at

v-u/t=a

a=4.9-2.4/0.5=0.1 m/s².

AGAIN,

v-u=at

v-u=0.1(2.5)

= 0.25 m/s