a certain force exerted for 1.2 seconds races the speed of an object from 1.8 metre per second to 4.2 metre per second find its acceleration. if mass of the object is 5.5 kg calculate the force applied.
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нєу тнєяє ιѕ αиѕωєя !!
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ι нσρє уσυ υи∂єяѕтαи∂ !!
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Here in this case the acceleration of the object is ,
a=v−ut=4·2−1·81·2=2 m/s2Now the mass of the object is 5·5 kg so the applied force is ,F=ma=5·5×2=11 N
яєgαя∂ѕ
мαяк мє вяαιи ℓιѕт !!
====================
ι нσρє уσυ υи∂єяѕтαи∂ !!
========================
Here in this case the acceleration of the object is ,
a=v−ut=4·2−1·81·2=2 m/s2Now the mass of the object is 5·5 kg so the applied force is ,F=ma=5·5×2=11 N
яєgαя∂ѕ
мαяк мє вяαιи ℓιѕт !!
mehtadaksh:
i understand it but your English is not understand able
ok
class 9
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