Question

A certain force is applied on a box of 50 Kg lying stationary on the ground. The force was applied for 2 sec. As a result the box started moving at 10 ms-1.Find the magnitude (measure) of force.​

Answer 1

Given:-

• Mass of box ,m = 50kg
• Time ,t = 2s
• Initial velocity ,u = 0m/s
• Final velocity ,v = 10m/s

To Find:-

• Magnitude of Force ,F

Solution:-

According to the Question

Firstly we calculate the acceleration produce in the box when force was applied on it .

• a = v-u/t

where,

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken

Substitute the value we get

$:\implies$ a = 10-0/2

$:\implies$ a = 10/2

$:\implies$ a = 5m/s²

Now, calculating the magnitude of Force .

Force is calculated by the product of mass & acceleration

• F = ma

where,

• F denote force
• m denote mass
• a denote acceleration

Substitute the value we get

$:\implies$ F = 50×5

$:\implies$ F = 250 N

• Hence, the magnitude of force was 250 Newton.

Answer 2

Answer:

250 N is the magnitude of force.

Explanation:

Given :-

A certain force is applied on a box of 50 Kg lying stationary on the ground. The force was applied for 2 sec. And the box started moving at 10 m/s.

To find :-

Magnitude of force.

Solution :-

Mass = 50 Kg

Time = 2 sec

Initial velocity = 0 m/s

Final velocity = 10 m/s

Acceleration = Change in velocity ÷ Time taken

• v - u/t
• 10 - 0/2
• 5

∴ Acceleration is 5 m/s².

Force = Mass × Acceleration

• 50 × 5
• 250

∴ Force is 250 N.