A certain force is exerted for 1.2s raises the speed of an object from 1.8 m/s to 4.2 m/s. Find its acceleration, if the mass of the object is 5.5 kg. Calculate the force applied.
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4
Answer:
acceleration =change in velocity/time
=(4.2-1.8)/1.2=2.4/1.2=2ms^-2
force=mass×acceleration
=5.5×2=11N
Answered by
3
a=v-u/t
a=4.2-1.8/1.2
acc.=2 m/s^2
Now force
F=ma
F= 5.5*2
F= 11 N
a=4.2-1.8/1.2
acc.=2 m/s^2
Now force
F=ma
F= 5.5*2
F= 11 N
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