Question

A certain force is exerted for 1.2s raises the speed of an object from 1.8m/s to 4.2m/s. After the same force is applied for 2s. How does the speed change in 2s ​

Answer 1

★ 4 m/s ★

Explanation:

Given:

• Initial speed (u) = 1.8 m/s
• Final speed (v) = 4.2 m/s
• Time (t) = 1.2 seconds
• Time (t²) = 2.0 seconds

To Calculate:

• Change in speed ( v – u ) = ?

Formula to be used:

$(1) \: a = \frac{v - u}{t}$

Substituting the values of v , u and t, we get

$\implies \: a \: = \: \frac{4.2 - 1.8}{2} \\ \\ \implies \: \frac{2.4}{1.2} = 2 \: m/s ^{2}$

Let "F" be the force which produces this acceleration, a = 2.0 m/s². Now the force "F" is acting on the body for t = 2.0 s.

$v - u = a \times t ^{1} \\ \\ v - u = 2 \times 2 \\ \\ v - u = 4 \: m/s$

Answer 2

Answer:

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Explanation:

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