Question

a certain force yesterday for 1.25 images of an object from 1.8 metre per second to 4.2 metre per second the same force is applied for to check how much speed change in2 second
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Answer 1

Explanation:

t=1.2s, u=1.8m//s, v= 4.2m//s`

acceleration, `a =(v-u)/t = (4.2-1.8)/(1.2)=(2.4)/(1.2)= 2m//s^(2)`

Now, aas force applied is the same, it will produce the same acceleration.

Change in speed=accelerationxxtime for which force is applied `=2xx2= 4m//s