Question

a certain forces acting on a body of mass 2kg increases its velocity from 6m/s to 15 m/s in 2 s the work done by the forces during this interval is

Answer 1

Given,mass(m)=2kg ,final velocity(v)=15 m/s, initial velocity(u)=6 m/s, time(t)=2 s

Force=ma ------(by formula)
F=m×(v-u)/t
F=2×(15-6)/2
F=2×(9)/2
F=2×4.5
F=9 Newton (N)

Force=9 Newton (N)