A certain gas takes 8 times as long to effuse out as compared to hydrogen gas for same volume at constant temperature and pressure . It's molecular mass will be?
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let the gas be a.
Then
rate(a)/rate(hydrogen)=
√molecular mass of hydrogen/√molecular mass of a. (1)
now,
rate(a)/rate(hydrogen)=8. (2)
from (1) and (2)
√molecular mass of a=√2/8
•hence molecular mass of gas a is 1/32 u
Then
rate(a)/rate(hydrogen)=
√molecular mass of hydrogen/√molecular mass of a. (1)
now,
rate(a)/rate(hydrogen)=8. (2)
from (1) and (2)
√molecular mass of a=√2/8
•hence molecular mass of gas a is 1/32 u
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