Question

A certain gas takes three times as long to effuse out as helium.Its molecular mass will be..?

Answer 1

Answer:Here is your Answer

Explanation:

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

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As per graham's law of diffusion

 

\frac{r_{1}}{r_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}

given that \frac{r_{1}}{r_{2}}={\frac{1}{3}}

M_{2}=4

\Rightarrow \frac{1}{3}=\sqrt{\frac{4}{M_{1}}}

\Rightarrow \frac{1}{9}={\frac{4}{M_{1}}}

\Rightarrow M_{1}=4\times 9 = 36