a certain gas takes three times as long to effuse out as Helium its molecular mass will be
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Answered by
61
You can use Graham's law of Effusion
Rate1 / Rate2 = square root of (Mass2 / Mass 1)
mass of helium = 4 units
Rate of He = 3 X Rate of unknown gas.
let the unknown gas has mass x
then
square root of (x / 4) = 3
x / 4 = 9
x = 9 X 4 = 36 g/mol
Rate1 / Rate2 = square root of (Mass2 / Mass 1)
mass of helium = 4 units
Rate of He = 3 X Rate of unknown gas.
let the unknown gas has mass x
then
square root of (x / 4) = 3
x / 4 = 9
x = 9 X 4 = 36 g/mol
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31
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