A certain group of welfare recipients receives snap benefits of $110 per week with a standard deviation of $20. If a random sample of 25 people is taken, what is the probability their mean benefit will be greater than $118 per week?
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Given:
Benefits = $110 per week
Standard deviation = $20
Number of people = 25
To find:
The probability their mean benefit will be greater than $118 per week
Solution:
Find z score,
Z score = ( Mean benefits - benefits ) / Standard deviation √ Number of people
( 118 - 110 ) / 20 √25
8 / ( 20 / 5)
8 / 4
2
Z score = 2
Using the z table, it is found that the z score of 2 approximately covers an area if 47.72 %
Hence,
Adding the 50 % on the left,
We get,
97.72 %
Hence, the probability their mean benefit will be greater than $118 per week is 97.72 %
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