A certain hydrocarbon has the following percentage composition C=83.73%, H=16.27%. The vapour density of the compound was found to be 42. [At. wt. of C=12, H=1] Find the molecular formula of the compound.
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Answer:
As we know,
Molar mass =2×vapour density
Molar mass of X =2×29=58gm
Mass of C =82.8×
100
58
=48gm
Mass of H =10gm
So, compound contains 4 C atoms and 10 H atoms and compound is C
4
H10.
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