Chemistry, asked by malti4singh, 10 months ago

A certain light bulb
containing argon at 1.25 atm and 18°C is heated to 85°C at constant volume. Calculate its final pressure (in
atm).

Answers

Answered by rosey25

Answer:

$<!DOCTYPE html><html lang="en"><head><title>Captain America Shield</title></head><div class="container"><div class="circle outer-lv3"><div class="circle outer-lv2"><div class="circle outer-lv1"><div class="center"><div class="arrow top"></div><div class="arrow left"></div><div class="arrow right"></div></div></div></div></div></div><style>html, body {background:#0846A8;height: 500px;}.container {width:100%;height: 100%;display: flex;justify-content: center;align-items: center;}.circle {border-radius: 50%;display: flex;flex-direction: row;justify-content: center;align-items: center;border:1px solid #000;}.outer-lv3 {background-image: linear-gradient(#870000,#FF4040,#870000);height: 260px;width: 260px;-webkit-animation: turning 8s infinite linear;animation: turning 8s infinite linear;}@-webkit-keyframes turning {0% {transform: rotate(0deg)}100% {transform: rotate(360deg)}}@keyframes turning {0% {transform: rotate(0deg)}100% {transform: rotate(360deg)}}.outer-lv2 {background: #fff;background-image: linear-gradient(#DBD9D9,#FAFAFA,#DBD9D9);height: 210px;width: 210px;}.outer-lv1 {background-image: linear-gradient(#870000,#FF4040,#870000);height: 150px;width: 150px;}.center {background-image: linear-gradient(#0846A8,#277AFF,#0846A8);height: 100px;width: 100px;border-radius: 50%;position: relative;overflow: hidden;border:1px solid #000;}.arrow {border-top: 35px solid #EDE8E8;border-bottom: 48px solid rgba(0,0,0,0.0);border-left: 48px solid transparent;border-right: 48px solid transparent;position: absolute;height: 0;width: 0;}.top {top: 35px;left: 2px;}.left {transform: rotate(72deg);top: 16px;left: -24px;}.right {transform: rotate(-72deg);top: 16px;left: 25px;}</style></body></html>$

The resulting pressure : 1.48 atm and enough to cause sudden break age of the bulb

Further explanation

There are several gas equations in various processes:

Based on Gay Lussac's Law

When the volume is not changed (constant), the gas pressure is proportional to its absolute temperature

\rm \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Light bulb containing argon gas, pressure 1.20 ATM at 18 ° c healed to 85 ° c at constant volume

Known

P1 = 1.20 atm

T1 = 18 °C + 273 = 291 K

T2 = 85 °C + 273 = 358 K

Asked

Answered by samueltriek

Answer:

Explanation:

p1 = 1.25atm p2 =
t1 = 18°c t2 = 85 + 273

= 358k

pressure is directly propotional to temperature

p1 / t1 = p2 / t2

p2 =p1 × t2 / t1

1.25atm × 358k / 291k

p2 = 1.53atm

Previous Question

Next Question

A certain light bulbcontaining argon at 1.25 atm and 18°C is heated to 85°C at constant volume. Calculate its final pressure (inatm).​

Answers

A certain light bulb
containing argon at 1.25 atm and 18°C is heated to 85°C at constant volume. Calculate its final pressure (in
atm).