Question

A certain machine has an efficiency of 48%. The
velocity ratio of the machine is 200. Find the effort
required to lift a load of 2 kN using this machine.​

Answer 1

Given : A certain machine has a efficiency of 48%

the velocity ratio of the machine is 200 .

To Find  :  the effort required to lift load of 2 kN using this machine.

​

Solution:

Let say  effort required to lift load of 2 kN using this machine. =  x N

V.R.= 200.    ( velocity ratio)

Hence Equivalent effort = 200x  N

efficiency  η  = 48  %

Then  (48/100)200x  = 96x N

2 kN = 2000N

=> 96x  = 2000

=> x = 2000/96

=> x = 125/6

=> x = 20.833  N

effort required to lift load of 2 KN using this machine.   20.833  N    or  125/6 N

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Answer 2

Explanation:

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