Question

A certain mass of a gas at 20°C is heated until both its pressure and volume are doubled. Calculate its final temperature.

Answer 1

Answer:

Explanation:

Given A certain mass of a gas at 20°C is heated until both its pressure and volume are doubled. Calculate its final temperature.

 We need to find the temperature. So, converting we get 20 + 273 = 293 k

We know that P1V1 / T1 = P2V2 / T2

Assume P1 and P2 as P and V1 and V2 as V

Substituting the values in the formula we get

P x V / 293 = 2P x 2V / T2

T2 / 293 = 2P x 2V / P x V

T2 = 293 x 4  

T2 = 1172 K

So after converting 1172 – 273 we get 899 degree celsius

So final temperature will be 899 degree celsius.

Answer 2

Answer:

Hy friend here is your answer

Explanation:

To find the temperature,

Converting =20+273

=293 k

Now, P1 V1 /T1 =P2 V2 /T2 , we know.

Assume P1 and P2 as [x] & V1 and V2 as [y].

Substituting the values in the formula,

x * y /293 =2x * 2y / T2

T2 /293 =2x *2y / x * y

T2 =293 *4

T2 =1172 k

I hope it is useful to you