Question

a certain mass of a gas occupied 850ml at a pressure of 760mm of hg on increasing the pressure it was found the volume of a gas was 75%of its initial value.Assuming constant temperature find the final pressure of the gas​

Answer 1

$\huge{\mathfrak{Question:-}}$

A certain mass of a gas occupied 850ml at a pressure of 760mm of Hg on increasing the pressure it was found the volume of a gas was 75%of its initial value. Assuming constant temperature find the final pressure of the gas.​

$\huge{\mathfrak{Answer:-}}$

To find final pressure of the gas we use Boyle's law.

The equation of Boyle's lawis as follows:

$\bold{=P_{1}V_{1} = P_{2} V_{2}}$

$\bold{P_{2}= P_{1}\times\frac{V_{1} }{Vx_{2}}\;\;\;\;\;\;\;..........(1)}$

$\large{\textsc{\underline{\underline{Given:-}}}}$

$\bold{V_{1} = 850\, ml}\\ \\ \bold{P_{1} = 760\, mm\, Hg}\\ \\ \bold{V_{2} = 75\%\;of\;850\,ml}\\ \\ \bold{= \frac{3}{4}\times 850\,ml}\\ \\ \bold{= 637.5\,ml}$

Putting the values in equation 1 we get,

$\bold{P_{2}= P_{1}\times\frac{V_{1} }{Vx_{2}}}$

$\bold{= 760\,mm\;Hg\times\frac{850\;ml.}{637.5\;ml}} \\ \\ \bold{=1013.33\,mm\;Hg}\\ \\ \bold{(760\,mm\;Hg = 1\;atm)}$

$\bold{\boxed{\boxed{\bold{= 1.3\;atm}}}}$

Answer 2

Answer:

1013 mm

Step By Step Explanation:

Given:

$\mathsf {P_1 = 760 \: mm}$

$\mathsf{ V _1 = 850 \:ml}$

$\mathsf{ V_2 = \frac{75}{10 \cancel0} \times 85 \cancel0} = \mathsf{ \frac{75 \times 85}{100} }$

$\mathsf {P_2 = \: ? }$

We have,

$\mathsf {P_1 V_1} = \mathsf {P_2 V_2}$

$\mathsf{ \implies 760 \times \cancel{ 850} = P_2 \times \mathsf{ \frac{75 \times \cancel{85}}{100} }}$

$\mathsf{ \implies \frac{760 \times 10 \times 10}{75} = P _2}$

$\mathsf{ \implies \frac{76000 }{75} = P _2}$

$\mathsf{ \implies P _2 = 1013 \:mm}$

Hence, The required final pressure of the gas is 1013 mm.